From a point $(1,0)$ on the circle $x^2+y^2-2 x+2 y+1=0$ if chords are drawn to this circle, then locus of…
From a point $(1,0)$ on the circle $x^2+y^2-2 x+2 y+1=0$ if chords are drawn to this circle, then locus of the poles of these chords with respect the circle $x^2+y^2=4$ is
$x=4$
$x+2 y=5$
$x^2+y^2-x-y=0$
$2 y^2=(x+1)$
Solution
Chord from point $(1,0)$ on the circle $x^2+y^2-2 x+2 y+1=0$ is polar on the circle $x^2+y^2=4$
So, locus of poles of the chords is equation of polar at $(1,0)$ on the circle $x^2+y^2=4$ i.e., $x=4$.
