From a disc of radius R and mass M , a circular hole of diameter R , whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre?

Question

Aicharya · Accepted Answer

I = M R 2 2 - 3 σ 2 π R 2 2 R 2 2 Where σ = M π R 2 I = M R 2 2 - 3 32 M R 2 I = 13 32 M R 2

From a disc of radius R and mass M , a circular hole of diameter R , whose rim passes through the centre is…

Solution