From \(6.55 \mathrm{~g}\) of aniline, the maximum amount of acetanilide that can be prepared will be ______…
Solution

$93 \mathrm{~g}$ aniline form $135 \mathrm{gm}$ acetanlide so $\quad 6.55 \mathrm{~g}$ anilne form $\frac{135}{93} \times 6.55=9.5$ $95 \times 10^{-1}$
Asked in: JEE Main 2024 (04 Apr Shift 2)