From \(6.55 \mathrm{~g}\) of aniline, the maximum amount of acetanilide that can be prepared will be ______…

From \(6.55 \mathrm{~g}\) of aniline, the maximum amount of acetanilide that can be prepared will be ______ \(\times 10^{-1} \mathrm{~g}\).

Solution


$93 \mathrm{~g}$ aniline form $135 \mathrm{gm}$ acetanlide so $\quad 6.55 \mathrm{~g}$ anilne form $\frac{135}{93} \times 6.55=9.5$ $95 \times 10^{-1}$

Asked in: JEE Main 2024 (04 Apr Shift 2)

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