Four resistors $A, B, C$ and $D$ form a Wheatstones bridge. The bridge is balanced, when $C=100 \Omega$. If $A$ and $B$ are interchanged, the bridge balances for $C=121 \Omega$. The value of $D$ is

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Aicharya · Accepted Answer

Balancing condition of bridge balance $\begin{aligned} \frac{A}{B} & =\frac{100}{x} \ \frac{B}{A} & =\frac{121}{x} \ 	herefore \quad \frac{100}{x} & =\frac{x}{121} \ x^2 & =12100 \ x & =110 \Omega\end{aligned}$

Four resistors $A, B, C$ and $D$ form a Wheatstones bridge. The bridge is balanced, when $C=100 \Omega$. If…

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