Four resistors $A, B, C$ and $D$ form a Wheatstone bridge as shown in the figure. The bridge is balanced when $C=100 \Omega$. If $A$ and $B$ are interchanged, the bridge balances for $C=121 \Omega$. The value of $D$ is

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Aicharya · Accepted Answer

According to the question, balanced wheat stone bridge, can be shows as follows

First case when, $C=100 \Omega$ Now, By balanced wheat stone bridge,

Second case when, $C=121 \Omega$ $ \frac{R_B}{R_A}=\frac{121}{R} $ From Eqs. (i) and (ii), we get $ \begin{aligned} \therefore \quad R & =\sqrt{100 \times 121} \\ R & =110 \Omega \end{aligned} $

Four resistors $A, B, C$ and $D$ form a Wheatstone bridge as shown in the figure. The bridge is balanced…

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