Four resistances of 15   Ω ,   12   Ω ,   4   Ω and 10   Ω…

Four resistances of 15 Ω, 12 Ω, 4 Ω and 10 Ω respectively in cyclic order to form Wheatstone’s network. The resistance that is to be connected in parallel with the resistance of 10 Ω to balance the network is ______________ Ω.

Solution


10R10+R×12=15×4
On solving
R=10 Ω

Asked in: JEE Main 2020 (08 Jan Shift 1)

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