Four point charges $-Q,-q, 2 q$ and $2 Q$ are placed, one at each corner of the square. The relation between…
- $Q=-q$
- $Q=-\frac{1}{q}$
- $Q=q$
- $Q=\frac{1}{q}$
Solution

If potential at centre is zero, then $\begin{aligned} V_1+V_2+V_3+V_4 & =0 \\ -\frac{k Q}{r}-\frac{k q}{r}+\frac{k 2 Q}{r}+\frac{k 2 q}{r} & =0 \\ -Q-q+2 q+2 Q & =0 \\ Q & =-q \end{aligned}$
Asked in: NEET 2012 (Screening)