Four particles each of mass M , move along a circle of radius R under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is :

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Aicharya · Accepted Answer

. F net&#160; = F 1 + 2 &#160; F 2 cos 45 &#176; = G M 2 ( 2 R ) 2 + 2 &#215; G M 2 ( 2 R ) 2 &#215; 1 2 = G M 2 4 R 2 + G M 2 2 R 2 = ( 4 + 2 ) G M 2 4 2 R 2 Now F C = F net&#160; M V 2 R = ( 4 + 2 ) G M 2 4 2 R 2 V = ( 4 + 2 ) 4 2 G M R

Four particles each of mass M , move along a circle of radius R under the action of their mutual…

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