Four numbers are chosen at random from $\{1,2,3, \ldots, 40\}$. The probability that they are not…

Four numbers are chosen at random from $\{1,2,3, \ldots, 40\}$. The probability that they are not consecutive, is
  1. $\frac{1}{2470}$
  2. $\frac{4}{7969}$
  3. $\frac{2469}{2470}$
  4. $\frac{7965}{7969}$

Solution

Probability that four of the numbers are consecutive $=\frac{{ }^{37} C_1}{{ }^{40} C_4}$ Now, probability that four of the numbers are Now, probability that four of the numbers are consecutive $=1-\frac{{ }^{37} C_1}{{ }^{40} C_4}$ $=\frac{2469}{2470}$

Asked in: AP EAMCET 2007

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