Four massless springs whose force constants are $2 \mathrm{~K}, 2 \mathrm{~K}, \mathrm{~K}$ and $2…

Four massless springs whose force constants are $2 \mathrm{~K}, 2 \mathrm{~K}, \mathrm{~K}$ and $2 \mathrm{~K}$ respectively are attached to a mass $\mathrm{M}$ kept on a frictionless plane as shown in figure, If mass $M$ is displaced in horizontal direction then frequency of oscillating system is
  1. $\frac{1}{2 \pi} \sqrt{\frac{\mathrm{K}}{4 \mathrm{M}}}$
  2. $\frac{1}{2 \pi} \sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}}$
  3. $\frac{1}{2 \pi} \sqrt{\frac{\mathrm{K}}{7 \mathrm{M}}}$
  4. $\frac{1}{2 \pi} \sqrt{\frac{7 \mathrm{~K}}{\mathrm{M}}}$

Solution

On the right hand side of the block, springs are connected in parallel $\therefore \quad$ Their effective spring constant is given by $\begin{aligned} & \mathrm{K}_1=\mathrm{K}+2 \mathrm{~K} \\ & \mathrm{~K}_1=3 \mathrm{~K} \end{aligned}$ On the left hand side of the block, springs are connected in series. $\therefore \quad$ Their effective spring constant is given by, $\begin{aligned} & \frac{1}{\mathrm{~K}_2}=\frac{1}{2 \mathrm{~K}}+\frac{1}{2 \mathrm{~K}} \\ \therefore \quad \mathrm{K}_2 & =\mathrm{K} \end{aligned}$ $\therefore \quad$ Effective spring constant of the system is given by, $\begin{aligned} & \mathrm{K}_{\mathrm{E}}=3 \mathrm{~K}+\mathrm{K}=4 \mathrm{~K} \\ \therefore \quad \omega & =\sqrt{\frac{\mathrm{K}_{\mathrm{E}}}{\mathrm{M}}}=\sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}} \\ \therefore \quad \mathrm{f} & =\frac{\omega}{2 \pi}=\frac{1}{2 \pi} \sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}} \end{aligned}$

Asked in: MHT CET 2023 (12 May Shift 1)

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