Four identical particles of equal masses 1   kg made to move along the circumference of a circle of radius 1   m under the action of their own mutual gravitational attraction. The speed of each particle will be:

Question

Four identical particles of equal masses 1 &#160; kg made to move along the circumference of a circle of radius 1 &#160; m under the action of their own mutual gravitational attraction. The speed of each particle will be:

Aicharya · Accepted Answer

F 1 = G m m 2 R 2 = G m 2 4 R 2 &#160; F 2 = G m m 2 R 2 = G m 2 2 R 2 &#160; F 3 = G m m 2 R 2 = G m 2 2 R 2 &#8658; F net = F 1 + F 2 cos 45 &#176; + F 3 cos 45 &#176; = G m 2 4 R 2 + G m 2 2 R 2 1 2 + G m 2 2 R 2 1 2 = G m 2 R 2 1 4 + 1 2 = G m 2 4 R 2 1 + 2 2 F net = G m 2 4 R 2 1 + 2 2 = m v 2 R &#8658; v = G 1 + 2 2 2

Four identical particles of equal masses 1   kg made to move along the circumference of a circle of…

Solution

Four identical particles of equal masses 1 &#160; kg made to move along the circumference of a circle of…

Solution

Four identical particles of equal masses 1 kg made to move along the circumference of a circle of…