Four identical capacitors are connected in series with a battery of \(16 \mathrm{~V}\) between…
Four identical capacitors are connected in series with a battery of \(16 \mathrm{~V}\) between \(\mathrm{A}\) and \(\mathrm{B}\) as shown in figure. If the point \(P\) is earthed, then the potential at \(A\) and \(B\) after the battery is disconnected, is
\(16 \mathrm{~V}, 0 \mathrm{~V}\)
\(12 \mathrm{~V},-12 \mathrm{~V}\)
\(12 \mathrm{~V},-4 \mathrm{~V}\)
\(8 \mathrm{~V},-8 \mathrm{~V}\)
Solution
The p.d. across each capacitor is \(4 \mathrm{~V}\). Since there are 3 capacitors between the point \(\mathrm{A}\) and the ground, the potential difference between A and ground is \(12+0=12 \mathrm{~V}\), the potential difference between ground and the point \(\mathrm{B}\) is \(0-4=-4 \mathrm{~V}\).
The potential at \(A\) is \(12 \mathrm{~V}\) and that at \(B\) is \(-4 \mathrm{~V}\)
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