Four condensers each of capacity $4 \mu \mathrm{F}$ are connected as shown in figure. $V_{P}-V_{Q}=15$ volts…

Four condensers each of capacity $4 \mu \mathrm{F}$ are connected as shown in figure. $V_{P}-V_{Q}=15$ volts. The energy stored in the system is
  1. 2400 ergs
  2. 1800 ergs
  3. 3600 ergs
  4. 5400 ergs

Solution

Total capacitance of given system $C_{e q}=\frac{8}{5} \mu \mathrm{F}$
$U=\frac{1}{2} C_{e q} V^{2}=\frac{1}{2} \times \frac{8}{5} \times 10^{-6} \times 225=180 \times 10^{-6} J=180 \times 10^{-6} \times 10^{7}$ erg $=1800 \mathrm{erg}$ *

Asked in: JEE Mains - Capacitance - Test 3

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