Four condensers each of capacitance $8 \mu \mathrm{~F}$ are joined as shown in the figure. The equivalent…

Four condensers each of capacitance $8 \mu \mathrm{~F}$ are joined as shown in the figure. The equivalent capacitance between the points A \& B will be

1. 32 mF
2. 2 mF
3. 8 mF
4. 16 mF

Solution

The equivalent circuit can be redrawn as
$\therefore$ The equivalent capacitance between A and B is $\mathrm{C}_{\mathrm{eq}}=4 \mathrm{C}=4 \times 8=32 \mu \mathrm{~F}$

Asked in: AP EAMCET 2024 (19 May Shift 2)

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