Four capacitors of equal capacity have an equivalent capacitance $\mathrm{C}_{1}$ when connected in series…
Four capacitors of equal capacity have an equivalent capacitance $\mathrm{C}_{1}$ when connected in series and an equivalent capacitance $\mathrm{C}_{2}$ when connected in parallel.
The ratio $\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$, is
4
12
16
8
Solution
Let capacitance of each capacitor is C. In series, equivalent capacitance
$C_{1}=\frac{C}{4}$
In parallel, equivalent capacitance
$\begin{aligned}
\mathrm{C}_{2} &=4 \mathrm{C} \\
\therefore \frac{\mathrm{C}_{1}}{\mathrm{C}_{2}} &=\frac{1}{16}
\end{aligned}$