Formation of a solution from two components can be considered as (i) Pure solvent $ightarrow$ separated…

Formation of a solution from two components can be considered as
(i) Pure solvent $ightarrow$ separated solvent molecules, $\Delta \mathrm{H}_{1}$
(ii) Pure solute $ightarrow$ separated solute molecules, $\Delta \mathrm{H}_{2}$
(iii) Separated solvent and solute molecules $ightarrow$ Solution, $\Delta \mathrm{H}_{3}$ Solution so formed will be ideal if
  1. $\Delta \mathrm{H}_{\text {soln }}=\Delta \mathrm{H}_{3}-\Delta \mathrm{H}_{1}-\Delta \mathrm{H}_{2}$
  2. $\Delta \mathrm{H}_{\text {soln }}=\Delta \mathrm{H}_{1}+\Delta \mathrm{H}_{2}+\Delta \mathrm{H}_{3}$
  3. $\Delta \mathrm{H}_{\text {soln }}=\Delta \mathrm{H}_{1}+\Delta \mathrm{H}_{2}-\Delta \mathrm{H}_{3}$
  4. $\Delta \mathrm{H}_{\text {soln }}=\Delta \mathrm{H}_{1}-\Delta \mathrm{H}_{2}-\Delta \mathrm{H}_{3}$

Solution

For an ideal solution, $\Delta \mathrm{H}_{\text {mixing }}=0$ $\Delta \mathrm{H}=\Delta \mathrm{H}_{1}+\Delta \mathrm{H}_{2}+\Delta \mathrm{H}_{3}$
(According to Hess's law)
i.e., for ideal solutions there is no change in magnitude of the attractive forces in the two components present. /

Asked in: JEE-TOPICTESTS-CHEMISTRY

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