$\mathrm{Ba}, \mathrm{Ca}, \mathrm{Sr}$ form halide hydrates. Their formulae are $\mathrm{BaCl}_2$, $x…
$\mathrm{Ba}, \mathrm{Ca}, \mathrm{Sr}$ form halide hydrates. Their formulae are $\mathrm{BaCl}_2$, $x \mathrm{H}_2 \mathrm{O}, \mathrm{CaCl}_2 y \mathrm{H}_2 \mathrm{O}, \mathrm{SrCl}_2, \mathrm{zH}_2 \mathrm{O}$. The values of $\mathrm{x}, \mathrm{y}, \mathrm{Z}$ respectively are
$2,6,6$
$8,6,2$
$8,6,6$
$6,4,2$
Solution
$\mathrm{BaCl}_2 \cdot 2 \mathrm{H}_2 \mathrm{O}, \mathrm{CaCl}_2 \cdot 6 \mathrm{H}_2 \mathrm{O}, \mathrm{SrCl}_2 \cdot 6 \mathrm{H}_2 \mathrm{O}$
so $x, y, z$ are $2,6,6$.