Force $F$ on a particle moving in a straight line varies with distance $d$ as shown in the figure. The work…
Force $F$ on a particle moving in a straight line varies with distance $d$ as shown in the figure. The work done on the particle during its displacement of $12 \mathrm{~m}$ is
$21 \mathrm{~J}$
$26 \mathrm{~J}$
$13 \mathrm{~J}$
$18 \mathrm{~J}$
Solution
Work done $=$ Area under $(F-x)$ graph
$\begin{aligned}
& =2 \times(7-3)+\frac{1}{2} \times 2 \times(12-7) \\
& =8+\frac{1}{2} \times 10 \\
& =8+5=13 \mathrm{~J}
\end{aligned}$
