Force between two point charges q 1 and q 2 placed in vacuum at r cm apart is F . Force between them when…

Force between two point charges q1 and q2 placed in vacuum at r cm apart is F. Force between them when placed in a medium having dielectric K=5 at r5 cm apart will be:
  1. F25
  2. 5F
  3. F5
  4. 25F

Solution

Using Coulomb's law, we can write:

In air F=14πε0q1q2r2

In medium F'=14πKε0q1q2r'2=14π5ε025q1q2r2=5F

Asked in: JEE Main 2024 (31 Jan Shift 2)

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