For $n \in N$, what is the value of $1+4+7+\cdots+(3 n-2)$

For $n \in N$, what is the value of $1+4+7+\cdots+(3 n-2)$
  1. $\frac{n(3 n+1)}{2}$
  2. $\frac{(3 n-1)}{2}$
  3. $\frac{n(3 n-1)}{2}$
  4. $\frac{(3 n+1)}{2}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

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