For triangle $ABC$ with $BC = 5$, $\angle B = 60^{\circ}$, $AB+AC = 8$, $XC$ is the segment from

For triangle $ABC$ with $BC = 5$, $\angle B = 60^{\circ}$, $AB+AC = 8$, $XC$ is the segment from
  1. $X$ (on ray) to $C$ (on base)
  2. $X$ to midpoint of $BC$
  3. $X$ to $A$
  4. $B$ to $C$

Solution

Connect the marked sum-point to the third vertex of the base.

Asked in: MH-SSC-9

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