For $\mathrm{Zn}^{2+} \mid \mathrm{Zn}, E^{\circ}=-0.76 \mathrm{~V}$ then EMF of the cell $\mathrm{Zn} /…

For $\mathrm{Zn}^{2+} \mid \mathrm{Zn}, E^{\circ}=-0.76 \mathrm{~V}$ then EMF of the cell $\mathrm{Zn} / \mathrm{Zn}^{2+}(1 \mathrm{M})\left|2 \mathrm{H}^{+}(1 \mathrm{M})\right| \mathrm{H}_2$ (1 atm) will be
  1. $-0.76 \mathrm{~V}$
  2. $0.76 \mathrm{~V}$
  3. $0.38 \mathrm{~V}$
  4. $-0.38 \mathrm{~V}$

Solution

\(\begin{aligned} E_{\text {cell }}^{\circ} & =E_{\text {right }}^{\circ}-E_{\text {left }}^{\circ} \\ E_{\text {cell }}^{\circ} & =0-(0-0.76)=0.76 V\end{aligned}\)

Asked in: NEET 2011 (Screening)

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