For the reaction: $\mathrm{NH}_{3}+\mathrm{OCl}^{-} \longrightarrow \mathrm{N}_{2}…
$\mathrm{NH}_{3}+\mathrm{OCl}^{-} \longrightarrow \mathrm{N}_{2} \mathrm{H}_{4}+\mathrm{Cl}^{-}$ in basic
medium, the coefficients of $\mathrm{NH}_{3}, \mathrm{OCl}^{-}$ and $\mathrm{N}_{2} \mathrm{H}_{4}$ for the balanced equation are respectively
- $2,2,2$
- $2,2,1$
- $2,1,1$
- $4,4,2$
Solution
$2 \mathrm{NH}_{3}+\mathrm{OCl}^{-} \longrightarrow \mathrm{N}_{2} \mathrm{H}_{4}+\mathrm{Cl}^{-}+\mathrm{H}_{2} \mathrm{O}$
Asked in: JEE-TOPICTESTS-CHEMISTRY