For the reaction $2 \mathrm{NO}+\mathrm{Cl}_2 \rightarrow 2 \mathrm{NOCl}$ What is the relation between…

For the reaction $2 \mathrm{NO}+\mathrm{Cl}_2 \rightarrow 2 \mathrm{NOCl}$ What is the relation between $\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}$ and $\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}$
  1. $\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=2 \frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}$
  2. $\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}$
  3. $\frac{1}{4} \frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}$
  4. $4 \frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}$

Solution

$2 \mathrm{NO}+\mathrm{Cl}_2 \longrightarrow 2 \mathrm{NOCl}$ Stoichiometric co-efficients of No and $\mathrm{NOCl}$ are same So their rates will be equal. $\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}$

Asked in: MHT CET 2021 (20 Sep Shift 1)

Practice more Chemical Kinetics questions on Aicharya