For the reaction, $2 \mathrm{~N}_2 \mathrm{O}_5 \rightarrow 4 \mathrm{NO}_2+\mathrm{O}_2$ rate of reaction is

For the reaction, $2 \mathrm{~N}_2 \mathrm{O}_5 \rightarrow 4 \mathrm{NO}_2+\mathrm{O}_2$ rate of reaction is
  1. $\frac{1}{2} \frac{d}{d t}\left[\mathrm{~N}_2 \mathrm{O}_5\right]$
  2. $2 \frac{d}{d t}\left[\mathrm{~N}_2 \mathrm{O}_5\right]$
  3. $\frac{1}{4} \frac{d}{d t}\left[\mathrm{NO}_2\right]$
  4. $4 \frac{d}{d t}\left[\mathrm{NO}_2\right]$

Solution

In general for a reaction, $x_1 A+x_2 B \rightarrow y_1 C+y_2 D$ The rate expression may be expressed as $-\frac{1}{x_1} \frac{d[A]}{d t}=-\frac{1}{x_2} \frac{d[B]}{d t}=\frac{1}{y_1} \frac{d[C]}{d t}=\frac{1}{y_2} \frac{d[D]}{d t} \text {. }$ For $2 \mathrm{~N}_2 \mathrm{O}_5 \rightarrow 4 \mathrm{NO}_2+\mathrm{O}_2$ $-\frac{1}{2} \frac{d\left[\mathrm{~N}_2 \mathrm{O}_5\right]}{d t}=\frac{1}{4} \frac{d\left[\mathrm{NO}_2\right]}{d t}=\frac{d\left[\mathrm{O}_2\right]}{d t}$

Asked in: MHT CET Full Test 2

Practice more Chemical Kinetics questions on Aicharya