For the reaction, $\mathrm{CH}_3 \mathrm{Br}_{(\mathrm{aq})}+\mathrm{OH}_{(\mathrm{aq})}^{-} \longrightarrow…

For the reaction, $\mathrm{CH}_3 \mathrm{Br}_{(\mathrm{aq})}+\mathrm{OH}_{(\mathrm{aq})}^{-} \longrightarrow \mathrm{CH}_3 \mathrm{OH}_{(\mathrm{aq})}+\mathrm{Br}_{(\mathrm{aq})}^{-}$ rate of consumption of $\mathrm{OH}_{(\mathrm{aq})}^{-}$is $\mathrm{x} \mathrm{mol} \mathrm{dm}{ }^{-3} \mathrm{~s}^{-1}$ What is the rate of formation of $\mathrm{Br}_{(\mathrm{aq})}^{-}$?
  1. $0.5 \mathrm{x} \mathrm{mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}$
  2. $\mathrm{x} \mathrm{mol} \mathrm{dm}{ }^{-3} \mathrm{~s}^{-1}$
  3. $2 \mathrm{x} \mathrm{mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}$
  4. $\frac{3}{2} \mathrm{x} \mathrm{mol} \mathrm{dm}^{-3} \mathrm{~s}^{-1}$

Solution

$\begin{aligned} & \text {Rate of consumption of }\left[\mathrm{OH}^{-}\right]=-\frac{\mathrm{d}\left[\mathrm{OH}^{-}\right]}{\mathrm{dt}} \\ & \text { Rate of formation of }\left[\mathrm{Br}^{-}\right] \\ & =\frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}=-\frac{\mathrm{d}\left[\mathrm{OH}^{-}\right]}{\mathrm{dt}}=\mathrm{x} \mathrm{mold} \mathrm{dm}^{-3} \mathrm{~s}^{-1}\end{aligned}$

Asked in: MHT CET 2024 (16 May Shift 2)

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