For the reaction $2 \mathrm{~N}_2 \mathrm{O}_{5(\mathrm{~g})} \longrightarrow 4…

For the reaction $2 \mathrm{~N}_2 \mathrm{O}_{5(\mathrm{~g})} \longrightarrow 4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$ rate and rate constant are $1.02 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ and $3.4 \times 10^{-5} \mathrm{~s}^{-1}$. What is the conc. of $\mathrm{N}_2 \mathrm{O}_5$ ?
  1. $1.7 \mathrm{~mol} \mathrm{~L}^{-1}$
  2. $3.0 \mathrm{~mol} \mathrm{~L}^{-1}$
  3. $3.4 \mathrm{~mol} \mathrm{~L}^{-1}$
  4. $5.1 \mathrm{~mol} \mathrm{~L}^{-1}$

Solution

$2 \mathrm{~N}_2 \mathrm{O}_{5(\mathrm{~g})} \rightarrow 4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$ $\because \quad$ It is a first order reaction, $\begin{array}{ll} & \text { Rate }=\mathrm{k}\left[\mathrm{~N}_2 \mathrm{O}_5\right] \\ \therefore \quad & 1.02 \times 10^{-4}=3.4 \times 10^{-5}\left[\mathrm{~N}_2 \mathrm{O}_5\right] \\ \therefore & {\left[\mathrm{N}_2 \mathrm{O}_5\right]=\frac{1.02 \times 10^{-4}}{3.4 \times 10^{-5}}=3.0 \mathrm{~mol} \mathrm{~L}^{-1}} \end{array}$

Asked in: MHT CET 2024 (04 May Shift 2)

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