For the reaction, $\mathrm{N}_2+3 \mathrm{H}_2 ightarrow 2 \mathrm{NH}_3$, If $\frac{\mathrm{d}\left[\mathrm{NH}_3 ight]}{\mathrm{dt}}=2 imes 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$, The value of $\frac{-\mathrm{d}\left[\mathrm{H}_2 ight]}{\mathrm{dt}}$ would be -

Question

For the reaction, $\mathrm{N}_2+3 \mathrm{H}_2 ightarrow 2 \mathrm{NH}_3$, If $\frac{\mathrm{d}\left[\mathrm{NH}_3ight]}{\mathrm{dt}}=2 	imes 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$, The value of $\frac{-\mathrm{d}\left[\mathrm{H}_2ight]}{\mathrm{dt}}$ would be -

Aicharya · Accepted Answer

$\begin{aligned} & \frac{1}{3} \frac{-\mathrm{d}\left[\mathrm{H}_2ight]}{\mathrm{dt}}=\frac{1}{2} \frac{\left[\mathrm{NH}_3ight]}{\mathrm{dt}} \ & \frac{-\mathrm{d}\left[\mathrm{H}_2ight]}{\mathrm{dt}}=\frac{3}{2} \frac{\mathrm{d}\left[\mathrm{NH}_3ight]}{\mathrm{dt}} \ & \frac{-\mathrm{d}\left[\mathrm{H}_2ight]}{\mathrm{dt}}=\frac{3}{2} 	imes 2 	imes 10^{-4} \ & =3 	imes 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \ & \end{aligned}$

For the reaction, $\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3$, If…

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