For the reaction given below, which of the following is not a possible product? $ \mathrm{H}_2…
For the reaction given below, which of the following is not a possible product?
$
\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2+\mathrm{Br}_2(a q) \xrightarrow{\mathrm{NaCl}} \text { Products }
$
Solution
$\mathrm{CH}_2=\mathrm{CH}_2+(a q) \mathrm{Br}_2 \xrightarrow{\mathrm{NaCl}} \mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}$
The $\pi$-electrons will attack an electrophile forming the carbocation.
Now, the carbocation will be attacked by a nucleophile.
Hence, the product will be a mixture of
$
\mathrm{Br}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}, \mathrm{Br}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Cl}
$
and $\mathrm{Br}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}$.
Hence, $\mathrm{Cl}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Cl}$ doesn't formed. Thus, the correct option is (4)
