For the reaction $\mathrm{PCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})} ightleftharpoons…

For the reaction $\mathrm{PCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})} ightleftharpoons \mathrm{PCl}_{5(\mathrm{~g})}$. The value of $\mathrm{K}_{\mathrm{c}}$ at $250^{\circ} \mathrm{C}$ is $26 .$ The value of $\mathrm{K}_{\mathrm{p}}$ at this temperature will be
  1. $0.61$
  2. $0.57$
  3. $0.83$
  4. $0.46$

Solution

$\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{\Delta \mathrm{n}}=26 \times(0.082 \times 523)^{-1}=0.61$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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