For the reaction \(\mathrm{A} \rightarrow\) products. The concentration of A at 10 minutes is _______…

For the reaction \(\mathrm{A} \rightarrow\) products.

The concentration of A at 10 minutes is _______ \(\times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1}\) (nearest integer).
The reaction was started with \(2.5 \mathrm{~mol} \mathrm{~L}^{-1}\) of A.

Solution

\(\begin{aligned}
& \mathrm{t}_{1 / 2} \propto[\mathrm{A}]_0 \Rightarrow \text { Order }=\text { zero } \\
& \mathrm{t}_{1 / 2}=\frac{\mathrm{A}_0}{2 \mathrm{~K}} \Rightarrow \text { Slope }=\frac{1}{2 \mathrm{~K}}=76.92 \\
& \mathrm{~K}=\frac{1}{2 \times 76.92} \\
& {[\mathrm{A}]_{10}=-\mathrm{Kt}+\mathrm{A}_0=-\frac{1}{2 \times 76.92} \times 10+2.5=2.435} \\
& =2435 \times 10^{-3} \mathrm{~mol} / \mathrm{L}
\end{aligned}\)

Asked in: JEE Main 2025 (02 Apr Shift 1)

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