For the reaction, 3A + 2B → C + D , the differential rate law can be written as :

1. $+\frac{1}{3}\frac{\text{d}\left[\text{A}\right]}{\text{dt}}=-\frac{\text{d}\left[\text{C}\right]}{\text{dt}}=\text{k}{\left[\text{A}\right]}^{\text{n}}{\left[\text{B}\right]}^{\text{m}}$
2. $\frac{1}{3}\frac{\text{d}\left[\text{A}\right]}{\text{dt}}=\frac{\text{d}\left[\text{C}\right]}{\text{dt}}=\text{k}{\left[\text{A}\right]}^{\text{n}}{\left[\text{B}\right]}^{\text{m}}$
3. $-\frac{1}{3}\frac{\text{d}\left[\text{A}\right]}{\text{dt}}=\frac{\text{d}\left[\text{C}\right]}{\text{dt}}=\text{k}{\left[\text{A}\right]}^{\text{n}}{\left[\text{B}\right]}^{\text{m}}$
4. $-\frac{\text{d}\left[\text{A}\right]}{\text{dt}}=\frac{\text{d}\left[\text{C}\right]}{\text{dt}}=\text{k}{\left[\text{A}\right]}^{\text{n}}{\left[\text{B}\right]}^{\text{m}}$

Solution

Asked in: JEE Main 2014 (19 Apr Online)

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