For the reaction. 2 H 2   g + O 2   g ⟶ 2 H 2 O   g ,   at   300   K ,…

For the reaction. 2H2 g+O2 g2H2O g, at 300 K, ΔG and ΔH of water are -228.4 kJ.mol-1  and -241.60 kJ.mol-1, respectively. Then calculate the value of change in entropy for the given reaction.
  1. +88 J/K
  2. +4.4 kJ/K
  3. -88 J/K
  4. -44 J/K

Solution

From the relation of thermodynamics, we have,

S= H - GT = -241.6 -(-228.4) × 103300 = -44 J/K

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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