For the random variable X with probability distribution is given by the table X = x 0 1 2 3 P ( X = x ) K K + 1 7 2   K 2 5 The mean of X is

Question

For the random variable X with probability distribution is given by the table X = x 0 1 2 3 P ( X = x ) K K + 1 7 2 &#160; K 2 5 The mean of X is

Aicharya · Accepted Answer

Given the distribution, X = x 0 1 2 3 P ( X = x ) K K + 1 7 2 &#160; K 2 5 As we know sum of all probabilities of an event is unity, &#8658; K + K + 1 7 + 2 K + 2 5 = 1 4 K = 1 - 1 7 + 2 5 = 1 - 19 35 4 K = 16 35 &#8658; K = 4 35 X = x 0 1 2 3 P ( X = x ) 4 35 9 35 8 35 2 5 Mean = &#8721; i = 0 3 x i p x i = 0 &#215; 4 35 + 1 &#215; 9 35 + 2 &#215; 8 35 + 3 &#215; 2 5 = 0 + 9 35 + 16 35 + 6 5 = 67 35

$X = x$	$0$	$1$	$2$	$3$
$P (X = x)$	$K$	$K + \frac{1}{7}$	$2 K$	$\frac{2}{5}$

$X = x$	$0$	$1$	$2$	$3$
$P (X = x)$	$K$	$K + \frac{1}{7}$	$2 K$	$\frac{2}{5}$

$X = x$	$0$	$1$	$2$	$3$
$P (X = x)$	$\frac{4}{35}$	$\frac{9}{35}$	$\frac{8}{35}$	$\frac{2}{5}$

For the random variable X with probability distribution is given by the table X = x 0 1 2 3 P ( X = x ) K K…

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