For the probability distribution The Expected value of X is

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Aicharya · Accepted Answer

The sum of all probabilities in a probability distribution is always unity. $\begin{aligned} 	herefore \quad \mathrm{k}+0.3 & +0.15+0.15+0.1+2 \mathrm{k}=1 \ \Rightarrow & 3 \mathrm{k} \ \Rightarrow & +0.7=1 \ \Rightarrow 3 \mathrm{k} & =0.3 \ \quad \Rightarrow \mathrm{k} & =0.1 \ 	herefore \quad \mathrm{E}(\mathrm{X}) & =\sum x_{\mathrm{i}} \cdot \mathrm{P}\left(x_{\mathrm{i}}ight) \ & =0(0.1)+1(0.3)+2(0.15)+3(0.15) \ & =0.3+0.3+0.45+0.4+1 \ & =2.45 \end{aligned}$

For the probability distribution The Expected value of X is

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