For the matrix $\mathrm{A}=\left[\begin{array}{ccc}2 & 0 & -1 \\ 3 & 1 & 2 \\ -1 & 1 & 2\end{array}\right]$,…
For the matrix $\mathrm{A}=\left[\begin{array}{ccc}2 & 0 & -1 \\ 3 & 1 & 2 \\ -1 & 1 & 2\end{array}\right]$, the matrix of cofactors is
- $\left[\begin{array}{ccc}0 & 8 & -4 \\ -1 & 3 & 2 \\ 1 & -7 & 2\end{array}\right]$
- $\left[\begin{array}{ccc}0 & -8 & 4 \\ -1 & 3 & -2 \\ 1 & -7 & 2\end{array}\right]$
- $\left[\begin{array}{ccc}0 & 8 & -4 \\ 1 & -3 & 2 \\ -1 & 7 & -2\end{array}\right]$
- $\left[\begin{array}{ccc}0 & -8 & 4 \\ -1 & 3 & 2 \\ -1 & -7 & 2\end{array}\right]$
Solution
$\begin{aligned} & \mathrm{A}_{11}=(-1)^{1+1}\left|\begin{array}{ll}1 & 2 \\ 1 & 2\end{array}\right|=1(0)=0 \\ & \mathrm{~A}_{12}=(-1)^{1+2}\left|\begin{array}{cc}3 & 2 \\ -1 & 2\end{array}\right|=(-1)(8)=-8 \\ & \mathrm{~A}_{13}=(-1)^{1+3}\left|\begin{array}{cc}3 & 1 \\ -1 & 1\end{array}\right|=(1)(4)=4 \\ & \mathrm{~A}_{21}=(-1)^{2+1}\left|\begin{array}{cc}0 & -1 \\ 1 & 2\end{array}\right|=(-1)(1)=-1 \\ & \mathrm{~A}_{22}=(-1)^{2+2}\left|\begin{array}{cc}2 & -1 \\ -1 & 2\end{array}\right|=(1)(3)=3 \\ & \mathrm{~A}_{23}=(-1)^{2+3}\left|\begin{array}{cc}2 & 0 \\ -1 & 1\end{array}\right|=(-1)(2)=-2 \\ & \mathrm{~A}_{31}=(-1)^{3+1}\left|\begin{array}{cc}0 & -1 \\ 1 & 2\end{array}\right|=(1)(1)=1 \\ & \mathrm{~A}_{32}=(-1)^{3+2}\left|\begin{array}{cc}2 & -1 \\ 3 & 2\end{array}\right|=(-1)(7)=-7 \\ & \mathrm{~A}_{33}=(-1)^{3+3}\left|\begin{array}{ll}2 & 0 \\ 3 & 1\end{array}\right|=(1)(2)=2\end{aligned}$
$\therefore \quad$ The matrix of the cofactors is $\left[\begin{array}{ccc}0 & -8 & 4 \\ -1 & 3 & -2 \\ 1 & -7 & 2\end{array}\right]$ :
Asked in: MHT CET 2024 (09 May Shift 2)
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