For the hyperbola $\frac{x^2}{\cos ^2 \alpha}-\frac{y^2}{\sin ^2 \alpha}=1$, which of the following remains…
For the hyperbola $\frac{x^2}{\cos ^2 \alpha}-\frac{y^2}{\sin ^2 \alpha}=1$, which of the following remains constant when $\alpha$ varies?
eccentricity
directrix
abscissae of vertices
abscissae of foci
Solution
$a^2=\cos ^2 \alpha$ and $b^2=\sin ^2 \alpha$
Coordinates of focii are $(\pm a e, 0)$
$\therefore b^2=a^2\left(e^2-1\right) \Rightarrow e=\sec \alpha$.
Hence abscissae of foci remain constant when $\alpha$ varies.