For the given input voltage waveform V in  ( t ) , the output voltage waveform V 0 ( t ) , across the capacitor is correctly depicted by :

Question

For the given input voltage waveform V in&#160; ( t ) , the output voltage waveform V 0 ( t ) , across the capacitor is correctly depicted by :

Aicharya · Accepted Answer

When first pulse is applied the potential across capacitor is given by $V = V_{0} (1 - e^{- \frac{t}{R C}})$

When no pulse is applied, capacitor will discharge like $V = V_{0}^{'} e^{t / R C}$ when again, second pulse is applied $V = V_{0} (1 - e^{- \frac{t}{R C}})$

Using all three equations the correct graph is :

For the given input voltage waveform V in  ( t ) , the output voltage waveform V 0 ( t ) , across the…

Solution

For the given input voltage waveform V in&#160; ( t ) , the output voltage waveform V 0 ( t ) , across the…

Solution

For the given input voltage waveform V in ( t ) , the output voltage waveform V 0 ( t ) , across the…