For the given cyclic process C A B as shown for a gas, the work done is:

The work done in a cyclic process is equal to the area of closed P-V curve cycle.

Work done, $W=$ Area of $∆CAB$

$\Rightarrow W=\frac{1}{2}\times AB\times AC$$=\frac{1}{2}\times (6-1)\times (5-1)=10 \mathrm{J}$

In the given P-V graph, the process is clockwise. So, the work done will be positive which means that the system is doing the work.