
For the given cycle, the work done during isobaric process is:

- $400 \mathrm{~J}$
- $600 \mathrm{~J}$
- $200 \mathrm{~J}$
- Zero
Solution

Work done in isobaric $(A B)$ process $\begin{aligned} & =P \Delta V \\ & =3 \times 10^2[2] \mathrm{J}=600 \mathrm{~J}\end{aligned}$ ~
Asked in: NEET 2023 (Manipur)