For the given cell $\mathrm{Fe}^{2+}{ }_{(\mathrm{aq})}+\mathrm{Ag}^{+}{ }_{(\mathrm{aq})} \rightarrow \mathrm{Fe}_{(\mathrm{aq})}^{3+}+\mathrm{Ag}_{(\mathrm{s})}$ The standard cell potential of the above reaction is Given: $\begin{array}{lr} \mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}…

Question

For the given cell
$\mathrm{Fe}^{2+}{ }_{(\mathrm{aq})}+\mathrm{Ag}^{+}{ }_{(\mathrm{aq})} \rightarrow \mathrm{Fe}_{(\mathrm{aq})}^{3+}+\mathrm{Ag}_{(\mathrm{s})}$
The standard cell potential of the above reaction is Given:
$\begin{array}{lr}
\mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag} & \mathrm{E}^\theta=\mathrm{xV} \\
\mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe} & \mathrm{E}^\theta=\mathrm{yV} \\
\mathrm{Fe}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} & \mathrm{E}^\theta=\mathrm{zV}
\end{array}$

Aicharya · Accepted Answer

$\mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Fe}^{3+}(\mathrm{aq})+\mathrm{Ag}(\mathrm{s})$

$\begin{aligned}
& \Delta \mathrm{G}_3^0=\Delta \mathrm{G}_1^0+\Delta \mathrm{G}_2^0 \\
& -3 \mathrm{~F}(-\mathrm{z})=-2 \mathrm{~F}(-\mathrm{y})+\Delta \mathrm{G}_2{ }^0 \\
& \Delta \mathrm{G}_2^0=3 \mathrm{Fz}-2 \mathrm{Fy}
\end{aligned}$
Also $\Delta \mathrm{G}_2^0=-\mathrm{nFE}_{\mathrm{Fe}^{+2} / \mathrm{Fe}^{t^{43}}}^0$
$\begin{aligned}
& 3 \mathrm{Fz}-2 \mathrm{Fy}=-1 \mathrm{~F}\left(\mathrm{E}_{\mathrm{Fe}^{t^2} / \mathrm{Fe}^{43}}^0\right) \\
& \mathrm{E}_{\mathrm{Fe}^{2+2} / \mathrm{Fe}^{t^3}}^0=2 \mathrm{y}-3 \mathrm{z}
\end{aligned}$
$\mathrm{E}_{\text {Cell }}^0$ for reaction will be
$\begin{aligned}
& \mathrm{E}_{\mathrm{Ag}^{+} / \mathrm{Ag}}^0+\mathrm{E}_{\mathrm{Fe}^{t^2 / \mathrm{Fe}}}^{03} \\
& =\mathrm{x}+2 \mathrm{y}-3 \mathrm{z}
\end{aligned}$

For the given cell $\mathrm{Fe}^{2+}{ }_{(\mathrm{aq})}+\mathrm{Ag}^{+}{ }_{(\mathrm{aq})} \rightarrow…

Solution