For the following combination of logic gates, when all the three inputs $A$, $B$ and $C$ are first 'high'…
For the following combination of logic gates, when all the three inputs $A$, $B$ and $C$ are first 'high' and then 'low', the output $Y$ will be respectively.
0,0
0,1
1,0
1,1
Solution
Let inputs $A, B$ and $C$ are given to the circuit.
Gate-I is AND gate while gate-II is NAND gate.
Output $Y=\overline{(A . B . C)}$
When $A=1, B=1, C=1$, then
$Y=\overline{(1 \cdot 1) \cdot 1}=\overline{1 \cdot 1}=\overline{1}=0$
When $A=0, B=0, C=0$, then
$Y=\overline{(0.0) \cdot 0}=\overline{0.0}=1$
