For the equilibrium $\mathrm{H}_2 \mathrm{O}_{(l)} \rightleftharpoons \mathrm{H}_2…
For the equilibrium $\mathrm{H}_2 \mathrm{O}_{(l)} \rightleftharpoons \mathrm{H}_2 \mathrm{O}_{(\mathrm{g})}$ at 1 atm and $298 \mathrm{~K}$,
standard free energy change is equal to zero $\left(\Delta G^{\circ}=0\right)$
free energy change is less than zero $(\Delta G < 0)$
standard free energy change is less than zero $\left(\Delta G^{\circ} < 0\right)$
standard free energy change is greater than zero $\left(\Delta G^{\circ} > 0\right)$.
Solution
$\mathrm{H}_2 \mathrm{O}_{(l)} \rightleftharpoons \mathrm{H}_2 \mathrm{O}_{(g)}$
This is a spontaneous process at standard conditions thus, the standard free energy change must be less then zero, i.e. $\Delta G^{\circ} < 0$.