For the equilibrium, A g ⇌ B g ,   ∆ H   is   - 40   kJ / mol . If the ratio of the activation energies of the forward E f and reverse E b reactions is 2 3 then:

Question

For the equilibrium, A g &#8652; B g , &#160; &#8710; H &#160; is &#160; - 40 &#160; kJ / mol . If the ratio of the activation energies of the forward E f and reverse E b reactions is 2 3 then:

Aicharya · Accepted Answer

Activation energy is the minimum amount of energy that must be provided for compounds to result in a chemical reaction.
$A (g) ⇌ B (g); ∆ H = - 40$ kJ/mole

$∆ H = E_{a (f)} - E_{a (b)} = - 40 k J$

$\frac{E_{a (f)}}{E_{a (b)}} = \frac{2}{3}$

$\Rightarrow E_{a (f)} = \frac{2}{3} E_{a (b)}$

$\Rightarrow \frac{2}{3} E_{a (b)} - E_{a (b)} = - \frac{E_{a (b)}}{3} = - 40 k J$

$E_{a (b)} = + 120 k J$

$E_{a (f)} = \frac{2}{3} \times 120 = 80 k J$

For the equilibrium, A g ⇌ B g ,   ∆ H   is   - 40   kJ / mol . If the ratio…

Solution

For the equilibrium, A g &#8652; B g , &#160; &#8710; H &#160; is &#160; - 40 &#160; kJ / mol . If the ratio…

Solution

For the equilibrium, A g ⇌ B g , ∆ H is - 40 kJ / mol . If the ratio…