For the electrochemical cell, $\mathrm{M}\left|\mathrm{M}^{+} \| \mathrm{X}^{-}ight| \mathrm{X}$,…

For the electrochemical cell, $\mathrm{M}\left|\mathrm{M}^{+} \| \mathrm{X}^{-}ight| \mathrm{X}$,
$\mathrm{E}^{0} _{\mathrm{M}^{+} / \mathrm{M}}=0.44 \mathrm{V~and~} \mathrm{E}^{\mathrm{o}}_{\left(\mathrm{X} / \mathrm{X}^{-}ight)}=0.33 \mathrm{~V}$
From this data one can deduce that
  1. $\mathrm{M}+\mathrm{X} ightarrow \mathrm{M}^{+}+\mathrm{X}^{-}$ is the spontaneous reaction
  2. $\mathrm{M}^{+}+\mathrm{X}^{-} ightarrow \mathrm{M}+\mathrm{X}$ is the spontaneous reaction
  3. $\mathrm{E}_{\text {cell }}=0.77 \mathrm{~V}$
  4. $\mathrm{E}_{\text {cell }}=-0.77 \mathrm{~V}$

Solution

For, $\mathrm{M}^{+}+\mathrm{X}^{-} \longrightarrow \mathrm{M}+\mathrm{X}, \mathrm{E}_{\text {cell }}^{\mathrm{o}}=0.44-0.33=0.11 \mathrm{~V}$
is positive, hence reaction is spontaneous.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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