For the differential equation $\left[1-\left(\frac{d y}{d x}\right)^2\right]^{5 / 3}=8 \frac{d^2 y}{d x^2}$ has the order and degree

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Aicharya · Accepted Answer

$\begin{aligned} & \left\{1-\left(\frac{d y}{d x}ight)^2ight\}^{\frac{5}{3}}=8 \frac{d^2 y}{d x^2} \ & \Rightarrow\left\{1-\left(\frac{d y}{d x}ight)^2ight\}^5=8^3\left(\frac{d^2 y}{d x^2}ight)^3 \ & 	ext { order }=2 	ext { and degree }=3\end{aligned}$

For the differential equation $\left[1-\left(\frac{d y}{d x}\right)^2\right]^{5 / 3}=8 \frac{d^2 y}{d x^2}$…

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