For the combination of logic gates shown in the figure, the equivalent logic gate is

Question

Aicharya · Accepted Answer

$Y_1=A+B ; Y_2=A+B$, as gate 1 and 2 are OR gates. As gate 3 is NAND gate, its output will be $ \begin{aligned} Y & =\overline{Y_1 Y_2}=\bar{Y}_1+\bar{Y}_2=\overline{A+B \cdot A+B} \\ & =\overline{A+B}+\overline{A+B}=\overline{A+B} \end{aligned} $ Using De-Morgan's theorem and identity $ A+A=A \text {. } $ So, given output is that of NOR gate

For the combination of logic gates shown in the figure, the equivalent logic gate is

Solution