For the circle $x^2+y^2-9=0$, find the equation of the chord having $(1,2)$ as its mid-point.

For the circle $x^2+y^2-9=0$, find the equation of the chord having $(1,2)$ as its mid-point.
  1. $x+2 y+5=0$
  2. $x-3 y-5=0$
  3. $x-3 y+5=0$
  4. $x+2 y-5=0$

Solution

Equation of chord having mid-point $(1,2)$ w.r.t. circle $x^2+y^2-9=0$ is (1) $x+$ (2) $y-9=1^2+2^2-9$ $ \Rightarrow \quad x+2 y=5 $

Asked in: AP EAMCET 2020 (22 Sep Shift 1)

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