For reaction $\mathrm{RX}+\mathrm{OH}^{-} \rightarrow \mathrm{ROH}+\mathrm{X}^{-}$, Rate expression is…

For reaction $\mathrm{RX}+\mathrm{OH}^{-} \rightarrow \mathrm{ROH}+\mathrm{X}^{-}$, Rate expression is $\mathrm{R}=4.7 \times 10^{-5}[\mathrm{RX}]\left[\mathrm{OH}^{-}\right]+2.4 \times 10^{-5}[\mathrm{RX}]$. What $\%$ of reactant react by $S N^2$ mechanism when $\left[\mathrm{OH}^{-}\right]=0.001$ molar -
  1. 0.195
  2. 66.2
  3. 95.1
  4. 16.4

Solution

Fraction of reactant decomposing by $\mathrm{S}_{\mathrm{N}} 2$ mechanism $=\frac{4.7 \times 10^{-5}[\mathrm{RX}]\left[\mathrm{OH}^{-}\right]}{4.7 \times 10^{-5}[\mathrm{RX}]\left[\mathrm{OH}^{-}\right]+2.4 \times 10^{-5}[\mathrm{RX}]}$ Put $\left[\mathrm{OH}^{-}\right]=0.001 \mathrm{M}$

Asked in: AP EAMCET 2022 (05 Jul Shift 2)

Practice more Chemical Kinetics questions on Aicharya