For reaction $a A \rightarrow x P$, when $[A]=2.2 \mathrm{mM}$, the rate was found to be $2.4 \mathrm{mM}…

For reaction $a A \rightarrow x P$, when $[A]=2.2 \mathrm{mM}$, the rate was found to be $2.4 \mathrm{mM} \mathrm{s}^{-1}$. On reducing concentration of $A$ to half, the rate changes to $0.6 \mathrm{mM} \mathrm{s}^{-1}$. The order of reaction with respect to $A$ is
  1. 1.5
  2. 2.0
  3. 2.5
  4. 3.0

Solution

$a A \rightarrow x P$ Rate of reaction $=[A]^a$ Order of reaction $=a$ $[A]_1=2.2 \mathrm{mM}, r_1=2.4 \mathrm{mM} \mathrm{s}^{-1}$ $[A]_2=\frac{2.2}{2} \mathrm{mM}, r_2=0.6$ or $\frac{2.4}{4} \mathrm{mM} \mathrm{s}^{-1}$ On reducing the concentration of $A$ to half, the rate of reaction is decreased by four times. $\therefore$ Rate of reaction $\propto[A]^2$ $\Rightarrow$ Order of reaction $=2$

Asked in: NEET 2006

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